45x^2+9x-2=(15x-2)

Solution for 45x^2+9x-2=(15x-2) equation:

45x^2+9x-2=(15x-2)

We move all terms to the left:

45x^2+9x-2-((15x-2))=0


We calculate terms in parentheses: -((15x-2)), so:

(15x-2)

We get rid of parentheses

15x-2

Back to the equation:

-(15x-2)


We get rid of parentheses

45x^2+9x-15x+2-2=0

We add all the numbers together, and all the variables

45x^2-6x=0

a = 45; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·45·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*45}=\frac{0}{90}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*45}=\frac{12}{90}
=2/15
$